document.write( "Question 39780: driving from tilsa to detriot, jeff averaged 50mph. he figured that if he had average 60mph, his driving time would have decreased 3hrs. how far is it from tulsa to detriot? \n" ); document.write( "
Algebra.Com's Answer #25201 by checkley71(8403) ![]() You can put this solution on YOUR website! 50*X=60*(X-3) OR 50X=60X-180 OR 10X=180 OR X=18 OR 50*18=900 MILES\r \n" ); document.write( "\n" ); document.write( "60(18-3) OR 60*15=900 MILES\r \n" ); document.write( "\n" ); document.write( "IF IT TAKES X HOURS TO GET TO DETROIT @ 50 MILES PER HOUR THAN THE DISTANCE IS 50X\r \n" ); document.write( "\n" ); document.write( "IF IT TAKES X-3 HOURS @ 60 MILES PER HOUR TO GET TO DETROIT THAN THE DISTANCE ID 60(X-3) \r \n" ); document.write( "\n" ); document.write( "SEEING AS THE DISTANCES ARE THE SAME WE SET THESE TWO FACT EQUAL THUS WE HAVE\r \n" ); document.write( "\n" ); document.write( "50*X=60(X-3) OR 50X=60X-180 OR 50X-60X=-180 OR -10X=-180 OR 10X=180 OR X=180/10 OR X=18 HOURS TO DRIVE FROM TULSA TO DETROIT @ 50 MILES PER HOUR OR 18*50=900 \r \n" ); document.write( "\n" ); document.write( "60 MILES PER HOUR ONLY TAKES (18-3) OR 15 HOURS THUS 60*15=900 MILES \n" ); document.write( " |