document.write( "Question 352607: Find the vertex, the line of symmetry, the maxiumum or minimum value of the quadratic function, and graph the function.
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document.write( "f(x)=-2x^2+2x+3
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document.write( "The x-coordinate of the vertex is:
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document.write( "The y-coordinate of the vertex is:
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document.write( "The equation of the line of symmetry is x=
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document.write( "The maximum/minimum of f(x) is:
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document.write( "The value, f(1/2)=7/2 is minimum or maximum?\r
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document.write( "So far, I have tried to work the problem. This is what I have:
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document.write( "f(x)=-2x^2+2x+3, so you use (-b/2a,4ac-b^2/4a)
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document.write( "Therefore, if -b/2a=-(2)/2(-1)=1
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document.write( "Then put 1 back into the equation.
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document.write( "f(1)=-2(1)^2+2(1)+3
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document.write( "Using FOIL, I come up with 1.
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document.write( "This where I get confused. Is the x-coordinate 1? How do i come up with y-coordinate?
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document.write( "Is the line of symmetry also 1?
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document.write( "I think I confuse myself the most when I try to apply the FOIL method?\r
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document.write( "Any help is so very much appreciated! Thanks in advance! \n" );
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Algebra.Com's Answer #252005 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Find the vertex, the line of symmetry, the maxiumum or minimum value of the quadratic function, and graph the function. \n" ); document.write( "f(x)=-2x^2+2x+3 \n" ); document.write( "---- \n" ); document.write( "vertex occurs at x = -b/(2a) = -2/(2*-2) = 1/4 \n" ); document.write( "This is a maximum \n" ); document.write( "The x-coordinate of the vertex is:1/4 \n" ); document.write( "The y-coordinate of the vertex is:f(1/4) = 3.375 \n" ); document.write( "The equation of the line of symmetry is x= 1/4 \n" ); document.write( "The maximum/minimum of f(x) is: max = 3.375 \n" ); document.write( "The value, f(1/4)=3.375 is maximum because the coefficient of x^2 is negative. \n" ); document.write( "----- \n" ); document.write( " \n" ); document.write( "--- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |