document.write( "Question 5053: Q. Prove the following identity: 1 divided by 1+cosx = 1/sin^2x - 1/sinxtanx
\n" ); document.write( "I am at the dead end but these are my steps:
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\n" ); document.write( "1 divided by(sinx)(sinx)-1 divided by (sinx)(sinx/cosx)=
\n" ); document.write( "sin^2x+cos^2x divided by sin^2x - sin^2x+cos^2xdivided by (sin^2x/cosx)=
\n" ); document.write( "(sinx)(sinx)+(cosx)(cos)divided by (sinx)(sinx) - (sinx)(sinx) + (cosx)(cosx)(cosx)divided by (sinx)(sinx)=
\n" ); document.write( "sin^2x + cos^2x - sin^2x + cos^2x(cosx) divided by (sinx)(sinx)=
\n" ); document.write( "and here either
\n" ); document.write( "1 - cosx divided by sin^2x
\n" ); document.write( "or
\n" ); document.write( "2cos^2x(cosx)divided by sin^2x
\n" ); document.write( "--------
\n" ); document.write( "thanks mmm
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Algebra.Com's Answer #2520 by longjonsilver(2297)\"\" \"About 
You can put this solution on YOUR website!
in any proof, pick one of the 2 sides and manipulate it until you get the other side. Always start with the more complicated side too!\r
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\n" ); document.write( "\n" ); document.write( "Looking at your proof: \"1%2F%281%2Bcosx%29+=+1%2F%28sin%5E2%28x%29%29+-+1%2F%28sinxtanx%29\", the RighHand side looks more complicated, so i shall pick this..basically i have more things to work with...\r
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\n" ); document.write( "\n" ); document.write( "\"1%2F%28sin%5E2%28x%29%29+-+1%2F%28sinxtanx%29\". I shall use the facts that tanx = sinx/cosx and also \"sin%5E2%28x%29+%2B+cos%5E2%28x%29+=+1\".\r
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\n" ); document.write( "\n" ); document.write( "\"1%2F%28sin%5E2%28x%29%29+-+1%2F%28sinx%2Asinx%2Fcosx%29\"
\n" ); document.write( "\"1%2F%28sin%5E2%28x%29%29+-+cosx%2F%28sin%5E2%28x%29%29\"
\n" ); document.write( "\"%281+-+cosx%29%2F%28sin%5E2%28x%29%29\"
\n" ); document.write( "\"%281+-+cosx%29%2F%281+-+cos%5E2%28x%29%29\". Now factorise the denominator:\r
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\n" ); document.write( "\n" ); document.write( "\"%281+-+cosx%29%2F%28%281+-+cosx%29%281+%2B+cosx%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"1%2F%281+%2B+cosx%29\" QED\r
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\n" ); document.write( "\n" ); document.write( "jon.
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