document.write( "Question 352570: A radiator contains 25 quarts of water and anti-freeze solution, of which 60% (by volume) is anti-freeze. How much of this solution must be drained and replaced with water for the new solution to be 40% anti-freeze? \n" ); document.write( "
Algebra.Com's Answer #251999 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A radiator contains 25 quarts of water and anti-freeze solution, of which 60% (by volume) is anti-freeze. How much of this solution must be drained and replaced with water for the new solution to be 40% anti-freeze? \n" ); document.write( "----------------------- \n" ); document.write( "Equation: \n" ); document.write( "water -water + water = water \n" ); document.write( "0.40*25 - 0.40x + 1.00x = 0.60*25 \n" ); document.write( "----- \n" ); document.write( "Multiply thru by 100 to get: \n" ); document.write( "40*25 + 40x + 100x = 60*25 \n" ); document.write( "140x = 20*25 \n" ); document.write( "x = (1/7)25 \n" ); document.write( "x = 3.57 quarts of the original mix must be replaced \n" ); document.write( "============================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |