document.write( "Question 352570: A radiator contains 25 quarts of water and anti-freeze solution, of which 60% (by volume) is anti-freeze. How much of this solution must be drained and replaced with water for the new solution to be 40% anti-freeze? \n" ); document.write( "
Algebra.Com's Answer #251999 by stanbon(75887)\"\" \"About 
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A radiator contains 25 quarts of water and anti-freeze solution, of which 60% (by volume) is anti-freeze. How much of this solution must be drained and replaced with water for the new solution to be 40% anti-freeze?
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\n" ); document.write( "Equation:
\n" ); document.write( "water -water + water = water
\n" ); document.write( "0.40*25 - 0.40x + 1.00x = 0.60*25
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\n" ); document.write( "Multiply thru by 100 to get:
\n" ); document.write( "40*25 + 40x + 100x = 60*25
\n" ); document.write( "140x = 20*25
\n" ); document.write( "x = (1/7)25
\n" ); document.write( "x = 3.57 quarts of the original mix must be replaced
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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