document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=352571>Question 352571</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The difference of thrice the complement and twice the supplement is 65 more than<BR>\n" );
document.write( "twice the sum of the complement and<BR>\n" );
document.write( "supplement.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #251981 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=251981\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi,<BR>\n" );
document.write( "*Note:  Let x represent the angle.  (90 -x ) would be its complement and (180 - x) its supplement<BR>\n" );
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document.write( "Question States:  Write as you Read<BR>\n" );
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document.write( "3(90 -x )-2(180-x) = 2[(90 -x )+(180-x)] + 65<BR>\n" );
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document.write( "simplify and solve for x<BR>\n" );
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