document.write( "Question 352564: A bus travelled 150 miles at a certain speed. If the bus went 10 miles faster, travel time will be decreased by 30 minutes. What is the speed of the bus? \n" ); document.write( "
Algebra.Com's Answer #251946 by mananth(16949) You can put this solution on YOUR website! let speed of bus be x mph \n" ); document.write( "if it travels 10 mph faster then its speed = x+10 mph. \n" ); document.write( "distance = 150 miles. \n" ); document.write( "time taken with original speed - time taken with increased speed = 1/2 hour \n" ); document.write( "... \n" ); document.write( "time = distance /speed \n" ); document.write( "150/x - 150/(x+10)= 1/2 \n" ); document.write( "LCM = x(x+10) \n" ); document.write( "150(x+10)-150x/x(x+10) = 1/2 \n" ); document.write( "150x+1500 -150x = x(x+10) / 2 \n" ); document.write( "1500 *2 = x^2 +10x \n" ); document.write( "x^2+10x-3000 =0 \n" ); document.write( "x^2+60x-50x-3000=0 \n" ); document.write( "x(x+60)-50(x+60)=0 \n" ); document.write( "(x+60)(x-50)=0 \n" ); document.write( "x=50 mph the original speed.\r \n" ); document.write( "\n" ); document.write( ",,, \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |