document.write( "Question 352564: A bus travelled 150 miles at a certain speed. If the bus went 10 miles faster, travel time will be decreased by 30 minutes. What is the speed of the bus? \n" ); document.write( "
Algebra.Com's Answer #251946 by mananth(16949)\"\" \"About 
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let speed of bus be x mph
\n" ); document.write( "if it travels 10 mph faster then its speed = x+10 mph.
\n" ); document.write( "distance = 150 miles.
\n" ); document.write( "time taken with original speed - time taken with increased speed = 1/2 hour
\n" ); document.write( "...
\n" ); document.write( "time = distance /speed
\n" ); document.write( "150/x - 150/(x+10)= 1/2
\n" ); document.write( "LCM = x(x+10)
\n" ); document.write( "150(x+10)-150x/x(x+10) = 1/2
\n" ); document.write( "150x+1500 -150x = x(x+10) / 2
\n" ); document.write( "1500 *2 = x^2 +10x
\n" ); document.write( "x^2+10x-3000 =0
\n" ); document.write( "x^2+60x-50x-3000=0
\n" ); document.write( "x(x+60)-50(x+60)=0
\n" ); document.write( "(x+60)(x-50)=0
\n" ); document.write( "x=50 mph the original speed.\r
\n" ); document.write( "\n" ); document.write( ",,,
\n" ); document.write( "m.ananth@hotmail.ca
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