document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=352530>Question 352530</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find an equation for the circle. <BR>\n" );
document.write( "Center at ( 2, - 6), diameter of length 6.2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #251943 by </B><A HREF=/tutors/aboutme.mpl?userid=Waveez><B>Waveez(3)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Waveez><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Waveez><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=251943\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Eqn of Circle : (x-a)^2 + (y-b)^2 = r^2<BR>\n" );
document.write( "Centre of circle = (a,b) <BR>\n" );
document.write( "Therefore, a= 2 and b= -6<BR>\n" );
document.write( "r= radius<BR>\n" );
document.write( " = 1/2 of diameter<BR>\n" );
document.write( " = 1/2 (6.2)<BR>\n" );
document.write( " = 3.1\r<BR>\n" );
document.write( "\n" );
document.write( "Hence equation of circle is,<BR>\n" );
document.write( "(x-2)^2+ (y+6)^2 = (3.1)^2 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );