document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=352560>Question 352560</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if peter is 7 years older than sharon and john is twice as old as peter, work out how old peter is if the average of their ages is 19 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #251938 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=251938\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let sharon be x years<BR>\n" );
document.write( "Peter = x+7<BR>\n" );
document.write( "John = 2(x+7)<BR>\n" );
document.write( "...<BR>\n" );
document.write( "Average age = 19 <BR>\n" );
document.write( "so sum of their ages = 3*19 = 57<BR>\n" );
document.write( "x+x+7+2x+14=57<BR>\n" );
document.write( "4x+21=57<BR>\n" );
document.write( "4x=57-21<BR>\n" );
document.write( "4x=36<BR>\n" );
document.write( "x= 9  sharon's age<BR>\n" );
document.write( "..<BR>\n" );
document.write( "peter's age = x+7 = 16<BR>\n" );
document.write( "..<BR>\n" );
document.write( "John's age = 2(x+7)=32\r<BR>\n" );
document.write( "\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );