document.write( "Question 352471: the perimeter of a rectangle is 44 yards. the length is 2 yards more than three times the width. find the width of the rectangle \n" ); document.write( "
Algebra.Com's Answer #251889 by nyc_function(2741)![]() ![]() You can put this solution on YOUR website! Use P = 2L + 2W\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Length = 3x + 2\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "width = x\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "P = 44\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "44 = 2(3x + 2) + 2x\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Can you take it from here? \n" ); document.write( " |