document.write( "Question 352495: Hello, did I find the x and y intercepts of the equation properly?\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2+%2A+y+=+x%5E2+-+4y+-+2\"\r
\n" ); document.write( "\n" ); document.write( "x=0
\n" ); document.write( "\"0%5E2+%2A+y+=+0%5E2+-+4y+-+2\"
\n" ); document.write( "\"%28-1%2F2%29+=+y\"
\n" ); document.write( "y intercept: (0,\"-1%2F2\")\r
\n" ); document.write( "\n" ); document.write( "y=0
\n" ); document.write( "\"x%5E2+%280%29+=+x%5E2+-+4%280%29+-+2\"
\n" ); document.write( "\"x+=+sqrt%282%29\"
\n" ); document.write( "x intercept: (\"sqrt%282%29\", 0)\r
\n" ); document.write( "\n" ); document.write( "If I did this correctly, do I leave the \"sqrt%282%29\" in the x intercept coordinates or do I convert this to decimal form, 1.41?\r
\n" ); document.write( "\n" ); document.write( "Thanks and have a great night!
\n" ); document.write( "

Algebra.Com's Answer #251883 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
You're doing great, but you forgot about the \"plus/minus\" involved when taking the square root. So the solutions of the second equation should be \"x=sqrt%282%29\" or \"x=-sqrt%282%29\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "This means that the x-intercepts are and \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Also, feel free to check out my tutoring website\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Jim
\n" ); document.write( "
\n" );