document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=352483>Question 352483</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you determine rather to add or to subtract when you move the variable by undoing it? Example:\r<BR>\n" );
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document.write( "              11a - 3=5a + 9 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #251871 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=251871\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 11a - 3=5a + 9\r<BR>\n" );
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document.write( "When crossing the equal symbol, the signs of the terms and constants change to the opposite value.\r<BR>\n" );
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document.write( "We solve the equation by combining like terms.\r<BR>\n" );
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document.write( "11a - 5a = 9 + 3\r<BR>\n" );
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document.write( "Do you see that 5a became -5a and -3 became 3?\r<BR>\n" );
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document.write( "6a = 12\r<BR>\n" );
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document.write( "a = 12/6\r<BR>\n" );
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document.write( "a = 2 </SPAN>\n" );
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