document.write( "Question 352425: twice lisa's age is 11 more than jessica's age. the sum of lisa's age is twice jessica's age is 43. how old are the girls? \n" ); document.write( "
Algebra.Com's Answer #251858 by mananth(16946) You can put this solution on YOUR website! let jessica be x \n" ); document.write( "lisa be y \n" ); document.write( "2y=x+11 \n" ); document.write( "2y-x=11....................1 \n" ); document.write( "y+2x= 43...................2 \n" ); document.write( "... \n" ); document.write( "multiply (1) by 2 and add it to (2) \n" ); document.write( "4y-2x=22 \n" ); document.write( "add \n" ); document.write( "5y=43+22 \n" ); document.write( "5y=65 \n" ); document.write( "/5 \n" ); document.write( "y=13 lisa's age \n" ); document.write( "... \n" ); document.write( "plug value of y in (1) \n" ); document.write( "26-x=11 \n" ); document.write( "26-11=x \n" ); document.write( "x= 15 jessica's age \n" ); document.write( "... \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |