document.write( "Question 352425: twice lisa's age is 11 more than jessica's age. the sum of lisa's age is twice jessica's age is 43. how old are the girls? \n" ); document.write( "
Algebra.Com's Answer #251858 by mananth(16946)\"\" \"About 
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let jessica be x
\n" ); document.write( "lisa be y
\n" ); document.write( "2y=x+11
\n" ); document.write( "2y-x=11....................1
\n" ); document.write( "y+2x= 43...................2
\n" ); document.write( "...
\n" ); document.write( "multiply (1) by 2 and add it to (2)
\n" ); document.write( "4y-2x=22
\n" ); document.write( "add
\n" ); document.write( "5y=43+22
\n" ); document.write( "5y=65
\n" ); document.write( "/5
\n" ); document.write( "y=13 lisa's age
\n" ); document.write( "...
\n" ); document.write( "plug value of y in (1)
\n" ); document.write( "26-x=11
\n" ); document.write( "26-11=x
\n" ); document.write( "x= 15 jessica's age
\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca
\n" ); document.write( "
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