document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=352426>Question 352426</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me with this question! ( At 10 a.m a car leaves a house at a rate of 60 mi/hour. at the same time, another car leaves the same house at a rate of 50 mi/hour in the opposite direction. at what time will the cars be 330 miles apart?) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #251841 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=251841\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> speed of one car = 60 mph<BR>\n" );
document.write( "speed of other car = 50 mph.<BR>\n" );
document.write( "since they are traveling in opposite directions and co-linesr their effective speed will ne 50+60 =110 mph.<BR>\n" );
document.write( "Distance = 330 miles.<BR>\n" );
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document.write( "Time = distance/speed<BR>\n" );
document.write( "time = 330/110<BR>\n" );
document.write( "= 3hours.<BR>\n" );
document.write( "So at 1.00 pm they will be 330 miles apart.<BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
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