document.write( "Question 352279: A total of $7000 is invested:part at 10% and the remainder at 15%. How much is invested at each rate if the annual interest is $720? \n" ); document.write( "
Algebra.Com's Answer #251796 by checkley77(12844)\"\" \"About 
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.15x+.10(7,000-x)=720
\n" ); document.write( ".15x+700-.10x=720
\n" ); document.write( ".05x=720-700
\n" ); document.write( ".05x=20
\n" ); document.write( "x=20/.05
\n" ); document.write( "x=400 amount invested @ 15%.
\n" ); document.write( "7,000-400=6,600 amount invested @ 10%
\n" ); document.write( "Proof:
\n" ); document.write( ".15*400+.10*6,600=720
\n" ); document.write( "60+660=720
\n" ); document.write( "720=720
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