document.write( "Question 352279: A total of $7000 is invested:part at 10% and the remainder at 15%. How much is invested at each rate if the annual interest is $720? \n" ); document.write( "
Algebra.Com's Answer #251796 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! .15x+.10(7,000-x)=720 \n" ); document.write( ".15x+700-.10x=720 \n" ); document.write( ".05x=720-700 \n" ); document.write( ".05x=20 \n" ); document.write( "x=20/.05 \n" ); document.write( "x=400 amount invested @ 15%. \n" ); document.write( "7,000-400=6,600 amount invested @ 10% \n" ); document.write( "Proof: \n" ); document.write( ".15*400+.10*6,600=720 \n" ); document.write( "60+660=720 \n" ); document.write( "720=720 \n" ); document.write( " \n" ); document.write( " |