document.write( "Question 352147: a wallet has $460 in $5, $10, and $20 Bills. The number of $5 bills exceeds twice the number of $10 bills by 4, while the number of $20 bills is 6 fewer than the number of $10 bills. How many bills of each type are there? \n" ); document.write( "
Algebra.Com's Answer #251783 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! LET X= THE NUMBER OF $10 BILLS. \n" ); document.write( "20(X-6)+10X+5(2X+4)=460 \n" ); document.write( "20X-120+10X+10X+20=460 \n" ); document.write( "40X=460+120-20 \n" ); document.write( "40X=560 \n" ); document.write( "X=560/40 \n" ); document.write( "X=14 NUMBER OF $10 BILLS. \n" ); document.write( "14-6=8 NUMBER OF $20 BILLS. \n" ); document.write( "2*14+4=28+4=32 $5 BILLS. \n" ); document.write( "PROOF: \n" ); document.write( "20*8+14*10+5*32=460 \n" ); document.write( "160+140+160=460 \n" ); document.write( "460=460\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |