document.write( "Question 352147: a wallet has $460 in $5, $10, and $20 Bills. The number of $5 bills exceeds twice the number of $10 bills by 4, while the number of $20 bills is 6 fewer than the number of $10 bills. How many bills of each type are there? \n" ); document.write( "
Algebra.Com's Answer #251783 by checkley77(12844)\"\" \"About 
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LET X= THE NUMBER OF $10 BILLS.
\n" ); document.write( "20(X-6)+10X+5(2X+4)=460
\n" ); document.write( "20X-120+10X+10X+20=460
\n" ); document.write( "40X=460+120-20
\n" ); document.write( "40X=560
\n" ); document.write( "X=560/40
\n" ); document.write( "X=14 NUMBER OF $10 BILLS.
\n" ); document.write( "14-6=8 NUMBER OF $20 BILLS.
\n" ); document.write( "2*14+4=28+4=32 $5 BILLS.
\n" ); document.write( "PROOF:
\n" ); document.write( "20*8+14*10+5*32=460
\n" ); document.write( "160+140+160=460
\n" ); document.write( "460=460\r
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