document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=352240>Question 352240</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Mandy begins bicycling west at 30 mi/h at 11 a.m. If Liz leaves the same point 20 minutes later bicycling west at 36 mi/h, at what time will Liz catch up with Mandy? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #251739 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=251739\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> D=RT<BR>\n" );
document.write( "D=30T<BR>\n" );
document.write( "D=36(T-1/3)<BR>\n" );
document.write( "30T=36(T-1/3)<BR>\n" );
document.write( "30T=36T-12<BR>\n" );
document.write( "30T-36T=-12<BR>\n" );
document.write( "-6T=-12<BR>\n" );
document.write( "T=-12/-6<BR>\n" );
document.write( "T=2 HOURS THE SECOND CYCLIST WILL CATCH THE FIRST CYCLIST.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "30*2=36(2-1/3)<BR>\n" );
document.write( "60=36*5/3<BR>\n" );
document.write( "60=12*5<BR>\n" );
document.write( "60=60 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );