document.write( "Question 352189: In how many ways can a committee of 7 be formed if there are 10 dogs and 15 cats to choose from and the committee must consist of exactly 3 dogs and 4 cats? \n" ); document.write( "
Algebra.Com's Answer #251701 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "*Note: The probability of x successes in n trials is:
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\n" ); document.write( "P = nCx* \"p%5Ex\"*\"q%5E%28n-x%29\" where p and q are the probabilities of success and failure respectively.
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\n" ); document.write( "nCx = \"n%21%2F%28x%21%28n-x%29%21%29\"
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\n" ); document.write( "Question states p(dog drawn) = 10/25 0r .4 and q (cat drawn) = .6
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\n" ); document.write( "\n" ); document.write( "Probability (3 dogs and 4 cats) \r
\n" ); document.write( "\n" ); document.write( "7C3 = \"+7%21%2F%283%21%2A4%21%29%21=+35+\"
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\n" ); document.write( "P((3 dogs and 4 cats) = \"35%2A%28.4%29%5E3%2A%28.6%29%5E4\" = .29
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