document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=352040>Question 352040</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the nine different fruits in the equation represnt the number from 1 to 9.each fruit represent the same number throughout.If bluberry equals 3 and orange equla 1 what is the number to identify the pear?\r<BR>\n" );
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document.write( "strawberry -blueberry =banana<BR>\n" );
document.write( "orange +watermelon =apple<BR>\n" );
document.write( "watermelon * cherry =apple<BR>\n" );
document.write( "banana /blueberry =cherry<BR>\n" );
document.write( "pears =? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #251658 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=251658\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I JUST DISCOVERED THAT YOU ONLY HAVE 8 FRUITS ----NOT 9.  OR IS IT JUST ME?\r<BR>\n" );
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document.write( "strawberry-blueberry=banana---or strawberry-3=banana--------------eq1<BR>\n" );
document.write( "orange+watermelon=apple--- or 1+watermelon=apple------------------eq2<BR>\n" );
document.write( "watermelon*cherry=apple-------------------------------------------eq3<BR>\n" );
document.write( "banana/blueberry=cherry -or banana/3=cherry--or banana=3*cherry---eq4<BR>\n" );
document.write( "pear=?????\r<BR>\n" );
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document.write( "substitute from eq4, banana=3*cherry into eq1 and we get:\r<BR>\n" );
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document.write( "strawberry-3=3*cherry -or strawberry=3*cherry+3--------------eq4a<BR>\n" );
document.write( "ok, if we examine this, we can see that cherry cannot be >2. If cherry is greater than 2, say 4 (3 is already taken), then strawberry would be 3*4+3=15 and strawberry cannot be greater than 9.  Soooo cherry has to be 2 because 1 and 3 are already taken.  THEREFORE, that means that strawberry is 3*2+3=9\r<BR>\n" );
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document.write( "Now so far,we have<BR>\n" );
document.write( "orange 1<BR>\n" );
document.write( "cherry 2<BR>\n" );
document.write( "blueberry 3<BR>\n" );
document.write( "and strawberry 9\r<BR>\n" );
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document.write( "Next,look at eq4.  banana=3*cherry=3*2=6<BR>\n" );
document.write( "Now we add banana--6\r<BR>\n" );
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document.write( "Now, look at eq2 and eq3<BR>\n" );
document.write( "1+watermelon=apple and<BR>\n" );
document.write( "watermelon*cherry=apple or watermelon*2=apple<BR>\n" );
document.write( "1+watermelon=2*watermelon  subtract watermelon from each side<BR>\n" );
document.write( "1=2*watermelon-watermelon or<BR>\n" );
document.write( "watermelon=1<BR>\n" );
document.write( "WHOAAA!!!!!!!!!!!!!!!!!!!!!!!!!!\r<BR>\n" );
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document.write( "  </SPAN>\n" );
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