document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=352026>Question 352026</A>: <I><SPAN STYLE=\"word-break: break-all;\"> You are going to invest $30,000, part at 9% and part at 14%. What is the most that can be invested at 9% in order to make at least $3000 in interest per year? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #251652 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=251652\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You can define a variable.\r<BR>\n" );
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document.write( "Let x be the sum invested at 9% interest.\r<BR>\n" );
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document.write( "(30000-x) will be the sum invested at 14% interest.\r<BR>\n" );
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document.write( "The interest in the first case becomes: 9\r<BR>\n" );
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document.write( "The interest in the second case becomes: (30000 - x) times 14.\r<BR>\n" );
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document.write( "Total interest = (9x/100) + 14(3000 - x)/100\r<BR>\n" );
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document.write( "Now, equate to 3000 to find the value of x, the amount invested to 9% interest.\r<BR>\n" );
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document.write( "(9x/100) + 14(3000 - x)/100 = 3000\r<BR>\n" );
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document.write( "This gives you the greatest value invested at 9% interest to get 3000 interest per year.\r<BR>\n" );
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document.write( "If less is invested at 9%, more will be invested at 14% and you get a higher interest.\r<BR>\n" );
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document.write( "Ideally, if you want to make the most interest, put everything at 19 percent. </SPAN>\n" );
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