document.write( "Question 352140: a card is taken at random from a pack of cards and replaced. A second card is drawn. The probability of a diamond being drawn is one quarter. What is the probability that both cards are from the same suit? \n" ); document.write( "
Algebra.Com's Answer #251641 by sudhanshu_kmr(1152)![]() ![]() You can put this solution on YOUR website! As card is replaced, probability of both card are independent.\r \n" ); document.write( "\n" ); document.write( "Both cards should be either spade, club, diamond or heart.\r \n" ); document.write( "\n" ); document.write( " probability of first card is diamond = 1/4 , \n" ); document.write( " \n" ); document.write( " similarly for second card it is also 1/4\r \n" ); document.write( "\n" ); document.write( "there are equal number of spade, club, diamond or heart card in a pack.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Probability of both cards are spade = 1/4 * 1/4 = 1/16 \n" ); document.write( " \n" ); document.write( "similiary,probability for both cards are club = 1/16\r \n" ); document.write( "\n" ); document.write( " for both cards are diamond = 1/16\r \n" ); document.write( "\n" ); document.write( " for both cards are heart = 1/16\r \n" ); document.write( "\n" ); document.write( "now, probability of both cards are from same suit = 1 /16 + 1/16 + 1/16 + 1/16 \n" ); document.write( " \n" ); document.write( " = 4/16 \n" ); document.write( " \n" ); document.write( " = 1 /4 \r \n" ); document.write( "\n" ); document.write( "required probability is 1/4\r \n" ); document.write( "\n" ); document.write( "Sometimes there may be typing mistake in solution of a problem, so please ignore it. Understand the concept and try the problem yourself. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |