document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=352141>Question 352141</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a card is taken at random from a pack of cards and replaced. A second card is drawn. The probability of a diamond being drawn is one quarter. What is the probability that both cards are from different suits? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #251629 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=251629\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a card is taken at random from a pack of cards and replaced. A second card is drawn. The probability of a diamond being drawn is one quarter. What is the probability that both cards are from different suits?<BR>\n" );
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document.write( "P(both different) = 1 -P(both are same suit)<BR>\n" );
document.write( "= 1 - p(both hearts or both diamonds or both spades or both clubs)<BR>\n" );
document.write( "= 1 - (4*(1/4)^2)<BR>\n" );
document.write( "= 1 - (1/4)<BR>\n" );
document.write( "= 3/4<BR>\n" );
document.write( "=================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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