document.write( "Question 352085: I would like to know if I did the problem correctly:
\n" ); document.write( "Percentage of adults who drink alcohol. Of the 1516 adults interviewed, 985 said that they drank.
\n" ); document.write( "a. Determine a 95% confidnce interval for the proportion, p, of all Americans who drink alcohol.
\n" ); document.write( "b. Interpret results.
\n" ); document.write( "This is what I came up with:
\n" ); document.write( "N=1516, x=985 and n-x=531 Both x and n-x are at least 5
\n" ); document.write( "985/1516=0.6497; za/2=z0.025=1.96
\n" ); document.write( "(a) 0.6497-1.96sqrt0.6497(1-0.6497)/1516 to 0.6497+1.96sqrt0.6497
\n" ); document.write( ")/1516=6.35,0079
\n" ); document.write( "(b) we can be 95% confident that the proprotion of adults who drink alcohol is somewhere between those numbers.
\n" ); document.write( "Thank you for any help you can give me.
\n" ); document.write( "

Algebra.Com's Answer #251604 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
I would like to know if I did the problem correctly:
\n" ); document.write( "Percentage of adults who drink alcohol. Of the 1516 adults interviewed, 985 said that they drank.
\n" ); document.write( "a. Determine a 95% confidnce interval for the proportion, p, of all Americans who drink alcohol.
\n" ); document.write( "b. Interpret results.
\n" ); document.write( "This is what I came up with:
\n" ); document.write( "N=1516, x=985 and n-x=531 Both x and n-x are at least 5\r
\n" ); document.write( "\n" ); document.write( "985/1516=0.6497; za/2=z0.025=1.96
\n" ); document.write( "-----------------------------------
\n" ); document.write( "a)
\n" ); document.write( "p-hat = 0.6497
\n" ); document.write( "E = 1.96sqrt(0.6497*(1-0.5497)/1516) = 0.0240
\n" ); document.write( "95%CI: 0.6497-0.0240 < p < 0.6497+0.0240
\n" ); document.write( "95%CI: 0.6257 < p < 0.6737
\n" ); document.write( "-----------------------------------
\n" ); document.write( "(a) 0.6497-1.96sqrt0.6497(1-0.6497)/1516 to 0.6497+1.96sqrt0.6497
\n" ); document.write( ")/1516=6.35,0079\r
\n" ); document.write( "\n" ); document.write( "(b) we can be 95% confident that the proportion of adults who drink alcohol is somewhere between 0.6257 and 0.6737.
\n" ); document.write( "----
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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