document.write( "Question 352026: You are going to invest $30,000, part at 9% and part at 14%. What is the most that can be invested at 9% in order to make at least $3000 in interest per year? \n" ); document.write( "
Algebra.Com's Answer #251594 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! .14X+.09(30,000-X)>3,000 \n" ); document.write( ".14X+2,700-.08X>3,000 \n" ); document.write( ".06X>3,000-2,700 \n" ); document.write( ".06X>300 \n" ); document.write( "X>300/.06 \n" ); document.write( "X>5,000 AMOUNT INVESTED @ 14%. \n" ); document.write( "30,000-5,000=25,000 AMOUNT INVESTED @ 9%. \n" ); document.write( "PROOF: \n" ); document.write( "LET THE 9% INVESTMENT BE $24,999 & THE INVESTMENT @ 14% BE 5,001. \n" ); document.write( ".14*5,001+.09*24,999>3,000 \n" ); document.write( "700.14+2,249.91>3.000 \n" ); document.write( "2950.05<3,000 SHOWS THAT $1 LESS INVESTED @ 9% RESULTS IN LESS THAN $3,000 IN INTEREST.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |