document.write( "Question 352107: The perimeter of a rectangular dog run is 58 feet. The width is 5 feet more than the length. Waht are dimensions of the dog run? \n" ); document.write( "
Algebra.Com's Answer #251573 by checkley77(12844)\"\" \"About 
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W=L+5
\n" ); document.write( "2L+2W=58
\n" ); document.write( "2L+2(L+5)=58\2L+2L+10=58
\n" ); document.write( "2L+2L+10=58
\n" ); document.write( "4L=58-10
\n" ); document.write( "4L=48
\n" ); document.write( "L=48/4
\n" ); document.write( "L=12 ANS. FOR THE LENGTH.
\n" ); document.write( "W=12+5=17 ANS. FOR THE LENGTH.
\n" ); document.write( "PROOF:
\n" ); document.write( "2*12+2*17=58
\n" ); document.write( "24+34=58
\n" ); document.write( "58=58\r
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