document.write( "Question 352056: Two teams working together can complete the project in 45 days. Team A works for 18 days and team B works for 12 days and they complete 30% of the project. How long will each team take to complete the project when they work alone. \n" ); document.write( "
Algebra.Com's Answer #251546 by ptaylor(2198)\"\" \"About 
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Let x=amount of time it takes Team A working alone to complete the project
\n" ); document.write( "Then Team A works at the rate of 1/x of the project per day
\n" ); document.write( "And let y=amount of time it takes Team B working alone to complete the project
\n" ); document.write( "Then Team B works at the rate of 1/y of the project per day
\n" ); document.write( "Were are told that together the two teams can complete the project in 45 days
\n" ); document.write( "Then, together the two teams work at the rate of 1/45 of the project per day.
\n" ); document.write( "Soooo, our first equation is:\r
\n" ); document.write( "\n" ); document.write( "1/x + 1/y=1/45-----------------------------eq1\r
\n" ); document.write( "\n" ); document.write( "In 18 days, Team A completes (1/x)*18=18/x of the project
\n" ); document.write( "In 12 days team B completes (1/y)*12=12/y of the project
\n" ); document.write( "And we are told that this work completes 30% of the project.
\n" ); document.write( "Soooo, our second equation is:\r
\n" ); document.write( "\n" ); document.write( "18/x +12/y=0.3*1 (1 project, that is)--------eq2\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Multiply eq1 by 12 and then subtract it from eq2 and we get:
\n" ); document.write( "6/x =0.03
\n" ); document.write( "0.03x=6
\n" ); document.write( "x=200 days---time it takes team A working alone\r
\n" ); document.write( "\n" ); document.write( "substitute x=200 into eq1 and we get:\r
\n" ); document.write( "\n" ); document.write( "1/200+1/y=1/45 multiply each term by 200y
\n" ); document.write( "y+200=4.44y
\n" ); document.write( "3.44y=200
\n" ); document.write( "y=58.1 days ---time it takes team B working alone\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "(1/200)*45 +(1/58.1)*45=1 (project, that is)
\n" ); document.write( "0.225 + 0.775=1
\n" ); document.write( "~~~~~~1=1
\n" ); document.write( "Hope this helps---ptaylor
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