document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=352083>Question 352083</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Rosa's age is twice Rod's age and Lily's age is 5 years younger than Rosa. The sum of Rosa's and Rod's age is 3 less than twice Lily's age. Find the ages of the three. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #251543 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=251543\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let Rod's age = x<BR>\n" );
document.write( "Rosa's age = 2x<BR>\n" );
document.write( "Lily's age = 2x-5<BR>\n" );
document.write( "...<BR>\n" );
document.write( "2x+x=2(2x-5)-3<BR>\n" );
document.write( "3x=4x-10-3<BR>\n" );
document.write( "3x-4x=-13<BR>\n" );
document.write( "-x=-13<BR>\n" );
document.write( "x= 13 Rod's age<BR>\n" );
document.write( "Rosa = 13*2 = 26 years<BR>\n" );
document.write( "Lily = 2*13-5 = 21 years<BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );