document.write( "Question 351732: a line passes through a point (4,-2) and is parallel to the line containing (-1,4) and (2,-3), what is the standard form? \n" ); document.write( "

Algebra.Com's Answer #251380 by ewatrrr(24785) $\"\"$ $\"About$

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Hi,
\n" ); document.write( "*Note paralel lines have the same slop\r
\n" ); document.write( "\n" ); document.write( ".Using the point-slope form
\n" ); document.write( " $\"m+=%28y%5B2%5D+-+y%5B1%5D%29%2F%28x%5B2%5D+-+x%5B1%5D%29\"$
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\n" ); document.write( "finding the slope
\n" ); document.write( "(-1,4) and (2,-3),
\n" ); document.write( " $\"m+=%28%28-3%29+-+4%29%2F%282+-+%28-1%29%29\"$
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\n" ); document.write( "m = -7/3 (the slope of both lines) As the slope is negative, we know the line(s) slope to the left
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\n" ); document.write( "Using the standard slope-intercept form y = mx + b where m is the slope and b is the y- intercept(the value of y when the line passes thru the y-axis)
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\n" ); document.write( "for the New line
\n" ); document.write( "y = (-7/3)x + b
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\n" ); document.write( "Substituting Pt(4,-2) to solve for b
\n" ); document.write( "-2 = -28/3 + b
\n" ); document.write( "-6/3 + 28/3 = b
\n" ); document.write( "22/3 = b
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\n" ); document.write( "New line is:
\n" ); document.write( "y = (-7/3)x + 22/3
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\n" ); document.write( "Standar form would be
\n" ); document.write( "3y + 7x = 22 \n" ); document.write( "

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