document.write( "Question 351742: a nurse wishes to add water to 30 ounces of a 10% solution of benzalkonium chloride to dilute it to a 4% solution. How much water must she add? \n" ); document.write( "
Algebra.Com's Answer #251377 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! Hi, \n" ); document.write( "*Note: .10*30oz tells us how much benzalkonium chloride is in that total solution \n" ); document.write( ". \n" ); document.write( ".10*30oz = 3oz (there are 3 oz of benzalkonium chloride in that total solution)\r \n" ); document.write( "\n" ); document.write( ". \n" ); document.write( "Question speaks of making a new 4% solution \n" ); document.write( "Let x be the amount of that \"total\" solution \n" ); document.write( ". \n" ); document.write( ".04*x = 3oz (the actual amount of benzalkonium chloride stays the same) \n" ); document.write( ". \n" ); document.write( "x = 3oz/.04 = 75oz \n" ); document.write( "As we already have 30z of \"total\" solution, 45oz of water will need to be added \n" ); document.write( ". \n" ); document.write( "check your answer \n" ); document.write( ".04*75oz = the 3 oz of benzalkonium chloride in the \"new total\" solution \n" ); document.write( " |