document.write( "Question 351754: The perimeter of a standard high school basketball court is 268 ft. The length is 34 ft longer than the width. Find the dimensions of the court. \n" ); document.write( "
Algebra.Com's Answer #251376 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! L=W+28 \n" ); document.write( "2L+2W=P \n" ); document.write( "2(W+28)+2W=268 \n" ); document.write( "2W+56+2W=268 \n" ); document.write( "4W=268-56 \n" ); document.write( "4W=212 \n" ); document.write( "W=212/4 \n" ); document.write( "W=53 FT. ANS. FOR THE WIDTH. \n" ); document.write( "L=53+28=81 ANS. FOR THE LENGTH. \n" ); document.write( "PROOF: \n" ); document.write( "2*81+2*53=268 \n" ); document.write( "162+106=268 \n" ); document.write( "268=268 \n" ); document.write( " |