document.write( "Question 351754: The perimeter of a standard high school basketball court is 268 ft. The length is 34 ft longer than the width. Find the dimensions of the court. \n" ); document.write( "
Algebra.Com's Answer #251376 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
L=W+28
\n" ); document.write( "2L+2W=P
\n" ); document.write( "2(W+28)+2W=268
\n" ); document.write( "2W+56+2W=268
\n" ); document.write( "4W=268-56
\n" ); document.write( "4W=212
\n" ); document.write( "W=212/4
\n" ); document.write( "W=53 FT. ANS. FOR THE WIDTH.
\n" ); document.write( "L=53+28=81 ANS. FOR THE LENGTH.
\n" ); document.write( "PROOF:
\n" ); document.write( "2*81+2*53=268
\n" ); document.write( "162+106=268
\n" ); document.write( "268=268
\n" ); document.write( "
\n" );