document.write( "Question 351702: There are five chemistry instructors and six physics instructors at a college. If a committee of four instructors is selected, find the probability that at least one of them is a physics instructor. Express your answer as a fraction in lowest terms. \r
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document.write( "I keep trying to multiply 5/11^4 and then subtracting from one and I cant get the answer. I am so confused.\r
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document.write( "Also, this problem:If three cards are drawn from a deck and not replaced, find the probability of getting at least one spade. Express your answer as a fraction in lowest terms.\r
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document.write( "I tried multiplying 39/52^3 and then subtracting from 1 but thats not it either and I have to have both of these in fraction form. \n" );
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Algebra.Com's Answer #251367 by stanbon(75887) ![]() You can put this solution on YOUR website! There are five chemistry instructors and six physics instructors at a college. If a committee of four instructors is selected, find the probability that at least one of them is a physics instructor. Express your answer as a fraction in lowest terms. \n" ); document.write( "I keep trying to multiply 5/11^4 and then subtracting from one and I cant get the answer. I am so confused. \n" ); document.write( "------------------------- \n" ); document.write( "P(at least one physics) = 1 - P(no physics) \n" ); document.write( "--- \n" ); document.write( "= 1 - 5C4/11C4 \n" ); document.write( "= 1 - 0.0152 \n" ); document.write( "= 0.9848 \n" ); document.write( "= 1231/1250 \n" ); document.write( "===================================== \r \n" ); document.write( "\n" ); document.write( "Also, this problem:If three cards are drawn from a deck and not replaced, find the probability of getting at least one spade. Express your answer as a fraction in lowest terms. \n" ); document.write( "--- \n" ); document.write( "P(at least one spade in three) = 1 - P(no spades in three) \n" ); document.write( "--- \n" ); document.write( "= 1 - 39C3/52C3 \n" ); document.write( "= 1 - 0.4135 \n" ); document.write( "= 0.5865 \n" ); document.write( "= 997/1700 \n" ); document.write( "=============== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "I tried multiplying 39/52^3 and then subtracting from 1 but thats not it either and I have to have both of these in fraction form. \n" ); document.write( "0 solutions \n" ); document.write( " \n" ); document.write( " |