document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=351757>Question 351757</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given that f(x) =x^2-3 and g(x)=2x+1 find  <BR>\n" );
document.write( "1)(fg)(0)<BR>\n" );
document.write( "2)(f/g)(-squareroot3) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #251346 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=251346\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Given that f(x) =x^2-3 and g(x)=2x+1 find <BR>\n" );
document.write( "1)(fg)(0) = f[g(0)] = f[2*0+1) = f(1) = 1^2-3 = -2<BR>\n" );
document.write( "======================<BR>\n" );
document.write( " <BR>\n" );
document.write( "2)(f/g)(-squareroot3) = [f(-sqrt(3)]/g[(-sqrt(3)]<BR>\n" );
document.write( "---<BR>\n" );
document.write( "= (-sqrt(3))^2-3 / [2(-sqrt(3))+1]<BR>\n" );
document.write( "----<BR>\n" );
document.write( "= (3-3)/[-2sqrt(3)+1]<BR>\n" );
document.write( "---<BR>\n" );
document.write( "= 0<BR>\n" );
document.write( "============<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );