document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=5042>Question 5042</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If two planes leave the same airport at 1:00 PM, how many miles apart will they be at 3:00 PM if one travels directly north at 150 mph and the other travels directly west at 200 mph?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #2513 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=2513\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Plane A travels due north at 150 mph for 2 hours, it will go 300 miles.<BR>\n" );
document.write( "Plane B travels due west at 200 mph for 2 hours, it will go 400 miles. \r<BR>\n" );
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document.write( "Draw the two vectors and you will see that they make two sides of a right triangle.  The distance between the two planes at the end of two hours is just the hypotenuse of this triangle.\r<BR>\n" );
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document.write( "You could use the Pythagorean theorem (c^2 = a^2 + b^2) to find the distance...or you could recognise that 300 and 400  are two of a pythagorean triplet (300, 400, 500) and the third number of this triplet is 500.\r<BR>\n" );
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document.write( "So, the planes will be 500 miles aprt at the end of two hours. </SPAN>\n" );
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