document.write( "Question 351655: Three times one number added to five times another number is 54. The second number is two less than the first. Use a system of equations to find the numbers. \n" ); document.write( "
Algebra.Com's Answer #251280 by sudhanshu_kmr(1152)\"\" \"About 
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\n" ); document.write( "Let first number is x, second is y.\r
\n" ); document.write( "\n" ); document.write( "according to question
\n" ); document.write( " 3x + 5y = 54 .....(1)
\n" ); document.write( " x-2 = y ......(2)\r
\n" ); document.write( "\n" ); document.write( "now put y = x-2 in equation (1)\r
\n" ); document.write( "\n" ); document.write( "then 3x + 5(x-2) = 54\r
\n" ); document.write( "\n" ); document.write( " => 3x + 5x -10 = 54 \r
\n" ); document.write( "\n" ); document.write( " => 8x -10 = 54 \r
\n" ); document.write( "\n" ); document.write( " => 8x = 54 + 10\r
\n" ); document.write( "\n" ); document.write( " => x = 64/8 =8
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\n" ); document.write( " then y = x-2 = 8-2 = 6\r
\n" ); document.write( "\n" ); document.write( "so, first number is 8, second is 6.\r
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\n" ); document.write( "\n" ); document.write( "ometimes there may be typing mistake in solution of a problem, so please ignore it. Understand the concept and try the problem yourself.
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