document.write( "Question 39699: A corporate jet has a speed of 600 miles per hour in still air. The jet travels directly north and encouters a 70 mile per hour wind blowing due east. Find the resulting speed of the plane. Round your answer to the nearest mile per hour. \n" ); document.write( "
Algebra.Com's Answer #25126 by Paul(988)![]() ![]() ![]() You can put this solution on YOUR website! SPEED OF THE JET -->600mph. north (v) \n" ); document.write( "Speed of the wind --->70mph. east (w) \n" ); document.write( "Resulting speed ---> ||v||+||w|| \n" ); document.write( "Makes a 90 degree angle for wind and the jet hence resulting in a 45 degree angle. \n" ); document.write( "EQUATION: \n" ); document.write( "From cosine law: \n" ); document.write( "||v||+||w||²= \n" ); document.write( "||v||+||w||=553 (rounded) \n" ); document.write( "Hence, the resulting speed is 553 mph. \n" ); document.write( "Paul. \n" ); document.write( " |