document.write( "Question 39699: A corporate jet has a speed of 600 miles per hour in still air. The jet travels directly north and encouters a 70 mile per hour wind blowing due east. Find the resulting speed of the plane. Round your answer to the nearest mile per hour. \n" ); document.write( "
Algebra.Com's Answer #25126 by Paul(988)\"\" \"About 
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SPEED OF THE JET -->600mph. north (v)
\n" ); document.write( "Speed of the wind --->70mph. east (w)
\n" ); document.write( "Resulting speed ---> ||v||+||w||
\n" ); document.write( "Makes a 90 degree angle for wind and the jet hence resulting in a 45 degree angle.
\n" ); document.write( "EQUATION:
\n" ); document.write( "From cosine law:
\n" ); document.write( "||v||+||w||²=\"600%5E2%2B70%5E2-2%2870%29%28600%29cos45\"
\n" ); document.write( "||v||+||w||=553 (rounded)
\n" ); document.write( "Hence, the resulting speed is 553 mph.
\n" ); document.write( "Paul.
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