document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=351633>Question 351633</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solution A is 30% acid and solution B is 60% acid. How many gallons of each solution must be used to create a 60-gallon mixture that is 50% acid? please write the representation of this problem. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #251257 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=251257\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi,<BR>\n" );
document.write( "Let x be the 'total' amount of the 30% solution.  then the 'total' amount of the 60% solution would be (60gal - x)<BR>\n" );
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document.write( "Question states;<BR>\n" );
document.write( ".30x + .60(60gal - x) = .50*60gal<BR>\n" );
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document.write( "Solve for x and then determine the value (60gal- x),as well. </SPAN>\n" );
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