document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=351554>Question 351554</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An equilateral triangle with a perimeter of 24 square root (3) is inscribed in  circle . find  radius of the circle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #251198 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=251198\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi,<BR>\n" );
document.write( "Using Heron's formula will give us the Area:<BR>\n" );
document.write( "Note: the sides a, b, c are each = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=8%2Asqrt%283%29 ALIGN=MIDDLE  ALT=\"8%2Asqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > and the semi-perimeter = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=12%2Asqrt%283%29 ALIGN=MIDDLE  ALT=\"12%2Asqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > <BR>\n" );
document.write( ".<BR>\n" );
document.write( "applying Heron's formula<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A=+sqrt%28+12%2Asqrt%283%29%2A4%2Asqrt%283%29%2A4%2Asqrt%283%29%2A4%2Asqrt%283%29%29 ALIGN=MIDDLE  ALT=\"A=+sqrt%28+12%2Asqrt%283%29%2A4%2Asqrt%283%29%2A4%2Asqrt%283%29%2A4%2Asqrt%283%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A=+sqrt%28+12%2A+9%2A64%29 ALIGN=MIDDLE  ALT=\"A=+sqrt%28+12%2A+9%2A64%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A=+2%2A3%2A8+%2Asqrt%28+3%29=+48+%2Asqrt%283%29 ALIGN=MIDDLE  ALT=\"A=+2%2A3%2A8+%2Asqrt%28+3%29=+48+%2Asqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( ".\r<BR>\n" );
document.write( "\n" );
document.write( "The radius of the circumscribed circle is:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=R+=+%28a%2Ab%2Ac%29%2F%284A%29=+%288%2Asqrt%283%298%2Asqrt%283%29%2A8%2Asqrt%283%29%29%2F%284%2A48%2Asqrt%283%29%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" > <BR>\n" );
document.write( "simplify and solve for R  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );