document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=351499>Question 351499</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1.a piece of wire 44cm long is cut into two parts and each part is bent to form a square.if the total area of two square is 65sq.cm.find the perimeter of two square.<BR>\n" );
document.write( "2.a particle is projeced from ground level so that its height above the groungd afer t seonds is given by 20t-5t^2m. after how any seconds is it 15m above the ground?can you explain briefly why there are two possible answers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #251166 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=251166\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let one piece be x<BR>\n" );
document.write( "and other y<BR>\n" );
document.write( "x+y =44.............1<BR>\n" );
document.write( "x/4 is the length of one side <BR>\n" );
document.write( "s^2/16 = area of one square<BR>\n" );
document.write( "...<BR>\n" );
document.write( "y/4 is the length of side of second square<BR>\n" );
document.write( "y^2/16 = arae<BR>\n" );
document.write( "...<BR>\n" );
document.write( "x^2/16 + y^2/16 = 65<BR>\n" );
document.write( "x^2+y^2 = 16* 65=1040<BR>\n" );
document.write( "=(x+y)^2 - 2xy = 1040  ( x+y)=44<BR>\n" );
document.write( "=44^2 -2xy = 1040<BR>\n" );
document.write( "=1936-2xy = 1040<BR>\n" );
document.write( "-2xy = 1040-1936<BR>\n" );
document.write( "-2xy =-896<BR>\n" );
document.write( "xy = 448\r<BR>\n" );
document.write( "\n" );
document.write( "...<BR>\n" );
document.write( "x+y = 44<BR>\n" );
document.write( "xy = 448<BR>\n" );
document.write( "y = 4488/x<BR>\n" );
document.write( "x+ 448/x = 44<BR>\n" );
document.write( "x^2 + 448 =44x<BR>\n" );
document.write( "x^2-44x+448=0\r<BR>\n" );
document.write( "\n" );
document.write( "x^2-28x-16x+448=0<BR>\n" );
document.write( "x(x-28)-16(x-28)=0<BR>\n" );
document.write( "(x-28)(x-16)=0<BR>\n" );
document.write( "x = 16 OR 28  These are the perimeters of the squares<BR>\n" );
document.write( "m.ananth@hotmail.ca\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "20t-5t^2m =15<BR>\n" );
document.write( "5t^2-20t +15 =0<BR>\n" );
document.write( "/5<BR>\n" );
document.write( "t^2-4t+3=0<BR>\n" );
document.write( "t^2-3t-t+3=0<BR>\n" );
document.write( "t(t-3)-1(t-3)=0<BR>\n" );
document.write( "(t-3)(t-1)=0<BR>\n" );
document.write( "t=1 or t = 3<BR>\n" );
document.write( "Since what goes up has to come down the two times reflect one upwars and one while returnng after reaching maximum height.<BR>\n" );
document.write( "You also can see fro graph<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=graph%28+300%2C300%2C-10%2C10%2C-10%2C10%2C%28x%5E2--4x%2B3%29%29 ALIGN=MIDDLE  ALT=\"graph%28+300%2C300%2C-10%2C10%2C-10%2C10%2C%28x%5E2--4x%2B3%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );