document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=351455>Question 351455</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A craftman in a woodworking shop takes 45 minutes to produce 12 spice racks. how long, in hours, will it take him to produce 27 spice racks? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #251157 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=251157\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=time it takes, in hours, to produce 27 spice racks.<BR>\n" );
document.write( "If it takes the craftsman 3/4 hr to produce 12 spice racks, then he can produce one spice rack in (3/4)*(1/12) hr or 3/48 hr. so he works at the rate of 3/48 hour per spice rack or 48/3 spice rack per hour<BR>\n" );
document.write( "Sooo our equation to solve is:<BR>\n" );
document.write( "(48/3)*x=27 or<BR>\n" );
document.write( "48x=81<BR>\n" );
document.write( "x=1.6875 hours\r<BR>\n" );
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document.write( "Check<BR>\n" );
document.write( "If he produces 1 spice rack in 3/48 hr, then he produces 27 spice racks in (3/48)*27 hour or 81/48 hr\r<BR>\n" );
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document.write( "Hope this helps----ptaylor </SPAN>\n" );
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