document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=351528>Question 351528</A>: <I><SPAN STYLE=\"word-break: break-all;\"> pls. help me solve this problem<BR>\n" );
document.write( " thank you.\r<BR>\n" );
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document.write( "prob 1. A boat goes 6 miles downstream in a river in 30 minutes and returns upstream in 45 minutes. Find the speed of the boat in still water and the speed of the current. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #251151 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=251151\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> still water speed = xmph<BR>\n" );
document.write( "current speed = y mph<BR>\n" );
document.write( "...<BR>\n" );
document.write( "Time = distance / speed<BR>\n" );
document.write( "upstream time = 6/ (x-y ) =(3/4)<BR>\n" );
document.write( "3(x-y ) =6*4<BR>\n" );
document.write( "x-y = 8.................1<BR>\n" );
document.write( "downstream speed = 6/(x+y) = (1/2) <BR>\n" );
document.write( "x+y = 12.................2<BR>\n" );
document.write( "add 1 & 2<BR>\n" );
document.write( "2x=20<BR>\n" );
document.write( "x=10 mph speed of boat.<BR>\n" );
document.write( "x-y =8 <BR>\n" );
document.write( "so y =2 mph speed of current </SPAN>\n" );
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