document.write( "Question 351523: Monica is one year older than twice her sister's age. The difference of their ages is 18. Find theor present ages. \n" ); document.write( "
Algebra.Com's Answer #251150 by mananth(16946)\"\" \"About 
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monica x years
\n" ); document.write( "sister y years
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\n" ); document.write( "x=2y+1
\n" ); document.write( "x-2y=1................1
\n" ); document.write( "x-y = 18..............2
\n" ); document.write( "multiply equation by -1 and add it up to equation 2
\n" ); document.write( "-x+2y=-1
\n" ); document.write( "x-y = 18
\n" ); document.write( "y=17 sister's age
\n" ); document.write( "...
\n" ); document.write( "x-y 1=8
\n" ); document.write( "x=18+y
\n" ); document.write( "x=18+17 = 35 monica'a age
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\n" ); document.write( "OR\r
\n" ); document.write( "\n" ); document.write( "if sister is x years
\n" ); document.write( "monica = 2x+1
\n" ); document.write( "...
\n" ); document.write( "2x+1-x=18
\n" ); document.write( "x= 18-1
\n" ); document.write( "x= 17 years sister's age\r
\n" ); document.write( "\n" ); document.write( "2x+1= 2*17+1= 35 monica's age
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