document.write( "Question 351523: Monica is one year older than twice her sister's age. The difference of their ages is 18. Find theor present ages. \n" ); document.write( "
Algebra.Com's Answer #251150 by mananth(16946)![]() ![]() You can put this solution on YOUR website! monica x years \n" ); document.write( "sister y years \n" ); document.write( "... \n" ); document.write( "x=2y+1 \n" ); document.write( "x-2y=1................1 \n" ); document.write( "x-y = 18..............2 \n" ); document.write( "multiply equation by -1 and add it up to equation 2 \n" ); document.write( "-x+2y=-1 \n" ); document.write( "x-y = 18 \n" ); document.write( "y=17 sister's age \n" ); document.write( "... \n" ); document.write( "x-y 1=8 \n" ); document.write( "x=18+y \n" ); document.write( "x=18+17 = 35 monica'a age \n" ); document.write( "...... \n" ); document.write( "OR\r \n" ); document.write( "\n" ); document.write( "if sister is x years \n" ); document.write( "monica = 2x+1 \n" ); document.write( "... \n" ); document.write( "2x+1-x=18 \n" ); document.write( "x= 18-1 \n" ); document.write( "x= 17 years sister's age\r \n" ); document.write( "\n" ); document.write( "2x+1= 2*17+1= 35 monica's age \n" ); document.write( " |