document.write( "Question 351479: A solution of 70% alcohol is to be mixed with a solution of 34% alcohol to form 72 liters of a 47% solution. How many liters of the 70% solution must be used?\r
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Algebra.Com's Answer #251121 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
Hi,
\n" ); document.write( "Let x be the total amount of the 70% alcohol solution. then (72L -x) would be the total amount of the 34% alcoohol solution.
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\n" ); document.write( "question states:
\n" ); document.write( ".70*x + .34*(72L-x) = .47*72
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\n" ); document.write( "simplify and solve
\n" ); document.write( ".70*x + .34*72L- .34*x = .47*72L
\n" ); document.write( ".36*x = .47*72L - .34*72L
\n" ); document.write( ".36x = 9.36L
\n" ); document.write( "x = 26L (the amount of the 70% alcohol solution needed to be used)
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