document.write( "Question 351359: find 3 consecutive multiples of 3 such that 6 times the first is 48 greater than 4 times the third \n" ); document.write( "
Algebra.Com's Answer #251093 by checkley77(12844)\"\" \"About 
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LET 3 x+3 & X+6 BE THE 3 NUMBERS.
\n" ); document.write( "6X=4(X+6)+48
\n" ); document.write( "6X=4X+24+48
\n" ); document.write( "6X-4X=72
\n" ); document.write( "2X=72
\n" ); document.write( "X=72/2
\n" ); document.write( "X=36 ANS. FOR THE SMALLER NUMBER
\n" ); document.write( "36+6=42 ANS. FOR THE LARGER NUMBER.
\n" ); document.write( "PROOF:
\n" ); document.write( "6*36=4*42+48
\n" ); document.write( "216=168+48
\n" ); document.write( "216=216
\n" ); document.write( "
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