document.write( "Question 351359: find 3 consecutive multiples of 3 such that 6 times the first is 48 greater than 4 times the third \n" ); document.write( "
Algebra.Com's Answer #251093 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! LET 3 x+3 & X+6 BE THE 3 NUMBERS. \n" ); document.write( "6X=4(X+6)+48 \n" ); document.write( "6X=4X+24+48 \n" ); document.write( "6X-4X=72 \n" ); document.write( "2X=72 \n" ); document.write( "X=72/2 \n" ); document.write( "X=36 ANS. FOR THE SMALLER NUMBER \n" ); document.write( "36+6=42 ANS. FOR THE LARGER NUMBER. \n" ); document.write( "PROOF: \n" ); document.write( "6*36=4*42+48 \n" ); document.write( "216=168+48 \n" ); document.write( "216=216 \n" ); document.write( " |