document.write( "Question 39693: Gina is 9 years younger than her sister Brigget. Two years ago Brigget was twice as old as Gina was. how old is Gina now?\r
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Algebra.Com's Answer #25109 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Gina is 9 years younger than her sister Brigget. Two years ago Brigget was twice as old as Gina was. how old is Gina now?\r \n" ); document.write( "\n" ); document.write( "NOW Data: \n" ); document.write( "Brigget age = \"x\" \n" ); document.write( "Gina age is \"x-9\"\r \n" ); document.write( "\n" ); document.write( "TWO-YEARS AGO Data: \n" ); document.write( "Brigget age = \"x-2\" \n" ); document.write( "Gina age = \"x-9-2\"=\"x-11\"\r \n" ); document.write( "\n" ); document.write( "EQUATION: \n" ); document.write( " Two years ago Brigget was twice as old as Gina. \n" ); document.write( " x-2=2(x-11) \n" ); document.write( "x-2=2x-22 \n" ); document.write( "x=20 (Brigget's age NOW. \n" ); document.write( "x-9= 11(Gina's age NOW.\r \n" ); document.write( "\n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "B \n" ); document.write( " \n" ); document.write( " |