document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=351386>Question 351386</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A card is drawn and a die is thrown. Find the following probabilities:<BR>\n" );
document.write( "a) Drawing a spade and rolling a four<BR>\n" );
document.write( "b) Rolling an odd number and drawing an odd numbered card<BR>\n" );
document.write( "c) Rolling a factor of 12 and drawing a card that is a factor of twelve (exclude 1 in both cases) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #251084 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=251084\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a)\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "P(Spade and rolling a 4) = P(Spade)*P(rolling a 4) = (13/52)*(1/6) = 13/312\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Note: There are 13 spade cards out of a total of 52. So P(Spade) = 13/52. Also, I'm assuming that we're rolling a 6 sided die, which means that P(Rolling a 4) = 1/6\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "b)\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "P(Rolling an odd number and drawing an odd numbered card) = P(Rolling an odd number) * P(Drawing an odd numbered card) = (3/6)*(16/52) = 48/312 = 2/13\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Note: There 3 odd numbers on a die (1, 3, 5) out of 6. So P(Rolling an odd number) = 3/6\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Also, the odd numbered cards are: 3, 5, 7, 9 and there are 4 suits. So there are 4*4 = 16 odd cards out a total of 52. So P(Drawing an odd numbered card) = 16/52\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "c) \r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "I'll let you tackle this one. Let me know if you need help on it. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );