document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=351364>Question 351364</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Bret started on a 80-mile bicycle ride at 19 miles per hour. After a time he became a little tired and slowed down to 12 miles per hour for the rest of the trip. The entire trip of 80 miles took <BR>\n" );
document.write( "5 1/2 hours. How far had Bret ridden when he reduced his speed to 12 miles per hour? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #251082 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=251082\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> D=RT<BR>\n" );
document.write( "T=D/R<BR>\n" );
document.write( "5.5=(X/19)+(80-X)/12)]<BR>\n" );
document.write( "5.5=(12X+19(80-X)/19*12<BR>\n" );
document.write( "5.5=(12X+1,520-19X)/228<BR>\n" );
document.write( "5.5=(-7X+1,520)/228 CROSS MULTIPLY.<BR>\n" );
document.write( "-7X+1,520=228*5.5<BR>\n" );
document.write( "-7X=1254-1,520<BR>\n" );
document.write( "-7X=-266<BR>\n" );
document.write( "X=-266/-7<BR>\n" );
document.write( "X=38 MILES FOR THE 19 MPH LEG.<BR>\n" );
document.write( "80-38=42 MILES FOR THE 12 MPH LEG.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "5.5=38/19+42/12<BR>\n" );
document.write( "5.5=3+2.5<BR>\n" );
document.write( "5.5=5.5<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );