document.write( "Question 351365: How do you factor 2y^2-15y+12? \n" ); document.write( "
Algebra.Com's Answer #251073 by checkley77(12844)\"\" \"About 
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2y^2-15y+12
\n" ); document.write( "Use the formula below.
\n" ); document.write( "\"y+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "y=(15+-sqrt[-15^2-4*2*12])/2*2
\n" ); document.write( "y=(14+-sqrt[225-96])/4
\n" ); document.write( "y=(15+-sqrt129)/4
\n" ); document.write( "y=(15+-11.3578)/4
\n" ); document.write( "y=(15+11.3578)/4
\n" ); document.write( "y=26.3578/4
\n" ); document.write( "y=6.589 ans.
\n" ); document.write( "y=(15-11.3578)/4
\n" ); document.write( "y=3.64/4
\n" ); document.write( "y=.91 ans.\r
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