document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=351277>Question 351277</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Anne and Nancy use a metal alloy that is 15.04% copper to make jewelry. How many ounces of a 10% alloy must be mixed with a 17% alloy from 100 ounces of the desired alloy? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #251040 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=251040\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Anne and Nancy use a metal alloy that is 15.04% copper to make jewelry. How many ounces of a 10% alloy must be mixed with a 17% alloy from 100 ounces of the desired alloy?\r<BR>\n" );
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document.write( "Let x = amount of 17% alloy<BR>\n" );
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document.write( "100-x = amount of 10% alloy\r<BR>\n" );
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document.write( ".17x + .10(100-x) = .1504(100)\r<BR>\n" );
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document.write( ".17x + 10-.10x = 15.04\r<BR>\n" );
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document.write( ".07x + 10 = 15.04\r<BR>\n" );
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document.write( ".07x = 5.04\r<BR>\n" );
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document.write( "x = 5.04/.07<BR>\n" );
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document.write( "x = 72 ounces (17% alloy)\r<BR>\n" );
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document.write( "For 10% alloy:<BR>\n" );
document.write( "100-x = 100-72 = 28 ounces </SPAN>\n" );
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