document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=351274>Question 351274</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In a chemistry class, 3 liters of a 4% silver iodine solution must be mixed with a 10% solution to get a 6% solution. How many liters of the 10% solution are needed? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #251038 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=251038\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In a chemistry class, 3 liters of a 4% silver iodine solution must be mixed with a 10% solution to get a 6% solution. How many liters of the 10% solution are needed?\r<BR>\n" );
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document.write( "Let x = amount of 10% solution<BR>\n" );
document.write( "then<BR>\n" );
document.write( "3-x = amount of 4% solution\r<BR>\n" );
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document.write( ".10x + .04(3-x) = .06(3)<BR>\n" );
document.write( ".10x + .12-.04x = .18<BR>\n" );
document.write( ".06x + .12 = .18<BR>\n" );
document.write( ".06x = .06<BR>\n" );
document.write( "x = 1 liter (amount of 10% solution) </SPAN>\n" );
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