document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=39617>Question 39617</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The ratio of the volume of two spheres is 216:125. What is the ratio of their diameters? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #25102 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=25102\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The ratio of the volume of two spheres is 216:125. What is the ratio of their diameters?<BR>\n" );
document.write( "VOLUME =(4/3)PI*R^3...HENCE VOLUME IS PROPORTIONAL TO CUBE OF RADIUS AND HENCE DIAMETER.<BR>\n" );
document.write( "SO IF<BR>\n" );
document.write( "V1/V2=216/125...THEN<BR>\n" );
document.write( "D1/D2=CUBE ROOT OF (216/125)=6/5 </SPAN>\n" );
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