document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=5036>Question 5036</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of half number and its reciprocal is the same as 51 divided by the number. find the number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #2510 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=2510\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> From the problem description, you can write:<BR>\n" );
document.write( " n/2 + 1/n = 51/n where n is the unknown number.  Multiply through by n to clear the fractions.<BR>\n" );
document.write( "(n^2)/2 + 1 = 51  Now multiply through by 2.<BR>\n" );
document.write( "n^2 + 2 = 102  Subtract 2 from both sides.<BR>\n" );
document.write( "n^2 = 100  Take the square root of both sides.<BR>\n" );
document.write( "n = +/- 10\r<BR>\n" );
document.write( "\n" );
document.write( "Both 10 and -10 will work here. </SPAN>\n" );
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